Passer à la navigation principale Passer à la recherche Passer au contenu principal

Disjoint Paths in decomposable Digraphs

  • University of Southern Denmark
  • Scuola Superiore Sant'Anna

Résultats de recherche: Contribution à un journalArticleRevue par des pairs

Résumé

The k-linkage problem is as follows: given a digraph D=(V,A) and a collection of k terminal pairs (S1, t1,...,(Sk, tk) such that all these vertices are distinct; decide whether D has a collection of vertex disjoint paths P1, P2, ,...,PK such that Pi is from Si to ti for i[k]. A digraph is k-linked if it has a k-linkage for every choice of 2k distinct vertices and every choice of k pairs as above. The k-linkage problem is NP-complete already for K=2 [11] and there exists no function f(K) such that every f(K) -strong digraph has a k-linkage for every choice of 2k distinct vertices of D [17]. Recently, Chudnovsky et al. [9] gave a polynomial algorithm for the k-linkage problem for any fixed k in (a generalization of) semicomplete multipartite digraphs. In this article, we use their result as well as the classical polynomial algorithm for the case of acyclic digraphs by fortune et al. [11] to develop polynomial algorithms for the k-linkage problem in locally semicomplete digraphs and several classes of decomposable digraphs, including quasi-transitive digraphs and directed cographs. We also prove that the necessary condition of being (2k-1) -strong is also sufficient for round-decomposable digraphs to be k-linked, obtaining thus a best possible bound that improves a previous one of (3k-2). Finally we settle a conjecture from [3] by proving that every 5-strong locally semicomplete digraph is 2-linked. This bound is also best possible (already for tournaments) [1].

langue originaleAnglais
Pages (de - à)545-567
Nombre de pages23
journalJournal of Graph Theory
Volume85
Numéro de publication2
Les DOIs
étatPublié - 1 juin 2017
Modification externeOui

Empreinte digitale

Examiner les sujets de recherche de « Disjoint Paths in decomposable Digraphs ». Ensemble, ils forment une empreinte digitale unique.

Contient cette citation